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(R)=110R-0.15R^2
We move all terms to the left:
(R)-(110R-0.15R^2)=0
We get rid of parentheses
0.15R^2-110R+R=0
We add all the numbers together, and all the variables
0.15R^2-109R=0
a = 0.15; b = -109; c = 0;
Δ = b2-4ac
Δ = -1092-4·0.15·0
Δ = 11881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11881}=109$$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-109)-109}{2*0.15}=\frac{0}{0.3} =0 $$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-109)+109}{2*0.15}=\frac{218}{0.3} =726+0.20000000000002/0.3 $
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